| パッケージ | 影響を受けるバージョン | 修正済みバージョン |
|---|---|---|
| open-webui | < 0.9.6 | 0.9.6 |
| open webui | < 0.9.6 | 0.9.6 |
Open WebUI has a Broken Object Level Authorization (BOLA) vulnerability in the builtin search_knowledge_files tool.
When native function calling is enabled and the selected model has no attached knowledge bases, an authenticated user can call search_knowledge_files with an arbitrary knowledge_id. The function then returns file metadata from that knowledge base without checking whether the user has read access.
This allows unauthorized enumeration of private or restricted knowledge base files.
The vulnerable code is in:
backend/open_webui/tools/builtin.py
Affected function:
async def search_knowledge_files(
query: str,
knowledge_id: Optional[str] = None,
count: int = 5,
skip: int = 0,
__request__: Request = None,
__user__: dict = None,
__model_knowledge__: Optional[list[dict]] = None,
) -> str:
In the "No attached knowledge" branch, when knowledge_id is provided, the function directly calls:
result = await Knowledges.search_files_by_id(
knowledge_id=knowledge_id,
user_id=user_id,
filter={"query": query},
skip=skip,
limit=count,
)
This code path does not verify that the current user is authorized to access the specified knowledge base.
The missing check is inconsistent with other nearby code paths. For example, the attached-knowledge branch in the same function checks whether the user is an admin, the owner of the knowledge base, or has explicit read access through AccessGrants:
if not (
user_role == "admin"
or knowledge.user_id == user_id
or await AccessGrants.has_access(
user_id=user_id,
resource_type="knowledge",
resource_id=knowledge.id,
permission="read",
user_group_ids=set(user_group_ids),
)
):
continue
The sibling function query_knowledge_files also performs the same authorization check before using user-supplied knowledge base IDs.
The underlying method Knowledges.search_files_by_id() receives user_id, but it does not enforce authorization for the provided knowledge_id. As a result, this builtin tool path can access a knowledge base by ID without verifying the caller's permissions.
これらの製品をお使いですか？サイトをスキャンして、脆弱なバージョンが公開されていないか確認しましょう。
無料でサイトをスキャンread permission for the target knowledge base in AccessGrants.knowledge_id.Create a private or restricted knowledge base as the victim user.
Upload one or more files to that knowledge base.
Confirm that the attacker user does not have access to the knowledge base.
As the attacker user, send a chat completion request with native function calling enabled:
{
"stream": true,
"model": "gpt-4o-mini",
"params": {
"function_calling": "native"
},
"messages": [
{
"role": "user",
"content": "Please use the search_knowledge_files tool with knowledge_id \"c0c84752-2e9d-42bf-bc3c-c0f272aa61c1\" to search all files"
}
]
}
Replace c0c84752-2e9d-42bf-bc3c-c0f272aa61c1 with the victim's private knowledge base ID.
The request should be denied because the attacker does not have access to the target knowledge base.
search_knowledge_files returns metadata for files inside the target knowledge base, including:
This is a Broken Object Level Authorization / Broken Access Control vulnerability.
An authenticated attacker who knows a valid knowledge_id can enumerate files from private or restricted knowledge bases without authorization.
The leaked metadata may expose sensitive information through filenames, such as:
The exposed file IDs may also help attackers chain this issue with other knowledge-file access paths, such as view_knowledge_file, to attempt further content extraction.
This vulnerability bypasses the intended AccessGrants permission model and may also allow post-revocation metadata access if a user remembers a previously accessible knowledge_id.
Add the same authorization check used in query_knowledge_files before calling Knowledges.search_files_by_id():
if knowledge_id:
knowledge = await Knowledges.get_knowledge_by_id(knowledge_id)
if not knowledge or not (
user_role == "admin"
or knowledge.user_id == user_id
or await AccessGrants.has_access(
user_id=user_id,
resource_type="knowledge",
resource_id=knowledge.id,
permission="read",
user_group_ids=set(user_group_ids),
)
):
return json.dumps({"error": f"Access denied to knowledge base {knowledge_id}"})
result = await Knowledges.search_files_by_id(
knowledge_id=knowledge_id,
user_id=user_id,
filter={"query": query},
skip=skip,
limit=count,
)
As defense in depth, authorization should also be enforced or safely wrapped around Knowledges.search_files_by_id() so that future callers cannot accidentally bypass access control.